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Chemistry · PYQ NEET UG 2019(2)

हिन्दी

The major products C and D formed in the following reaction respectively are \( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{O}-\text{C}(\text{CH}_3)_3 \xrightarrow[\Delta]{\text{excess HI}} \text{C} + \text{D} \)

  1. A
    \( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{OH} \text{ and } \text{OH}-\text{C}(\text{CH}_3)_3 \)
  2. B
    \( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{I} \text{ and } \text{I}-\text{C}(\text{CH}_3)_3 \)
  3. C
    \( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{OH} \text{ and } \text{I}-\text{C}(\text{CH}_3)_3 \)
  4. D
    \( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{I} \text{ and } \text{HO}-\text{C}(\text{CH}_3)_3 \)
View Answer & Solution

Correct answer · Option B

\( \text{H}_3\text{C}-\text{CH}_2-\text{CH}_2-\text{I} \text{ and } \text{I}-\text{C}(\text{CH}_3)_3 \)

Explanation

Reaction of mixed ether with excess HI proceeds via an \( \text{S}_\text{N}1 \) mechanism for tertiary alkyl groups to form tert-butyl iodide and \( \text{S}_\text{N}2 \) for primary alkyl groups to form 1-iodopropane.
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