Chemistry · PYQ NEET UG 2019(2)

The molar solubility of \( \mathrm{CaF_2} \) \( (\mathrm{K_{sp}} = 5.3 \times 10^{-11}) \) in \( 0.1 \) \( \mathrm{M} \) solution of \( \mathrm{NaF} \) will be

1. A
   \( 5.3 \times 10^{-10} \) \( \mathrm{mol\,L^{-1}} \)
2. B
   \( 5.3 \times 10^{-11} \) \( \mathrm{mol\,L^{-1}} \)
3. C
   \( 5.3 \times 10^{-8} \) \( \mathrm{mol\,L^{-1}} \)
4. D
   \( 5.3 \times 10^{-9} \) \( \mathrm{mol\,L^{-1}} \)