OnlineCBT Logo OnlineCBT

Physics · JEE | LAWS OF MOTION

हिन्दी

The position coordinate of a particle of mass \( m \) moving along the y-axis is given by \( y = ut + \frac{1}{2}gt^2 \). The magnitude of the force acting on the particle is:

  1. A
    2mg
  2. B
    mg
  3. C
    zero
  4. D
    m(u + gt)
View Answer & Solution

Correct answer · Option B

mg

Explanation

Differentiating \( y \) twice with respect to \( t \) yields acceleration \( a = g \). Thus, force \( F = ma = mg \).
Address Contact

+91 9694780911

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 9694780911


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat