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Physics · JEE | Current Electricity

हिन्दी

The rate of electrical energy dissipated as heat in a resistor of resistance \( R \) carrying a current \( \varkappa \) (or \( I \)) is expressed as:

  1. A
    \( P = \frac{V}{I^2} \)
  2. B
    \( P = \frac{I}{R^2} \)
  3. C
    \( P = I R^2 \)
  4. D
    \( P = I^2 R = \frac{V^2}{R} \)
View Answer & Solution

Correct answer · Option D

\( P = I^2 R = \frac{V^2}{R} \)

Explanation

Using \( P = VI \) and Ohm's law \( V = IR \), power loss is \( P = I^2 R = \frac{V^2}{R} \).
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