OnlineCBT
Physics · PYQ NEET UG 2022
हिन्दीThe ratio of the distances travelled by a freely falling body in the \( 1^{\text{st}}, 2^{\text{nd}}, 3^{\text{rd}} \) and \( 4^{\text{th}} \) second:
View Answer & Solution
Correct answer · Option A
\( 1 : 3 : 5 : 7 \)
Explanation
The distance travelled in the \( n^{\text{th}} \) second is given by \( S_n = u + \frac{a}{2}(2n-1) \). For a freely falling body starting from rest, \( S_n \propto (2n-1) \), yielding \( 1 : 3 : 5 : 7 \).
