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Physics · Electrostatic Potential
हिन्दीThe region between the plates of an isolated parallel plate capacitor carrying charge \( Q \) has volume \( V_0 \). If the plate separation is doubled, what is the new electrostatic energy density in terms of the initial energy density \( u_0 \)?
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Correct answer · Option A
\( u_0 \)
Explanation
Energy density is \( u = \frac{1}{2} \varepsilon_0 E^2 \). For an isolated capacitor, \( E = \frac{\sigma}{\varepsilon_0} = \frac{Q}{\varepsilon_0 A} \), which is independent of the distance \( d \). Therefore, \( u = u_0 \).
