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Chemistry · PYQ NEET UG 2023
हिन्दीThe right option for the mass of \( \text{CO}_2 \) produced by heating \( 20\text{ g} \) of \( 20\% \) pure limestone is (Atomic mass of \( \text{Ca} = 40 \)) \( [\text{CaCO}_3 \xrightarrow{1200\text{ K}} \text{CaO} + \text{CO}_2] \)
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Correct answer · Option C
1.76 g
Explanation
Mass of pure \( \text{CaCO}_3 = 20 \times \frac{20}{100} = 4\text{ g} \). Moles of \( \text{CaCO}_3 = \frac{4}{100} = 0.04\text{ mol} \). Since 1 mole of \( \text{CaCO}_3 \) gives 1 mole of \( \text{CO}_2 \), mass of \( \text{CO}_2 = 0.04 \times 44 = 1.76\text{ g} \).
