Physics · JEE | Dual Nature of Radiation and Matter
हिन्दीThe slope of the straight-line graph plotted between the stopping potential \( V_0 \) and the frequency of incident radiation \( \nu \) for a given photosensitive material is equal to:
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Correct answer · Option D
\( \frac{h}{e} \)
Explanation
From \( e V_0 = h\nu - \phi_0 \), we get \( V_0 = (\frac{h}{e})\nu - \frac{\phi_0}{e} \), so the slope is \( \frac{h}{e} \).