OnlineCBT Logo OnlineCBT

Chemistry · EQUILIBRIUM

हिन्दी

The solubility of a salt \( \text{MX} \) of a weak monobasic acid \( \text{HX} \) depends on pH according to the relation \( S = \sqrt{K_{sp}(1 + \frac{[\text{H}^+]}{K_a})} \). If \( K_{sp} = 4.0 \times 10^{-10} \) and \( K_a = 1.0 \times 10^{-5} \), what is the molar solubility of \( \text{MX} \) at \( \text{pH} = 3.0 \)?

  1. A
    \( 2.0 \times 10^{-5}\text{ M} \)
  2. B
    \( 6.32 \times 10^{-4}\text{ M} \)
  3. C
    \( 2.01 \times 10^{-4}\text{ M} \)
  4. D
    \( 4.00 \times 10^{-3}\text{ M} \)
View Answer & Solution

Correct answer · Option C

\( 2.01 \times 10^{-4}\text{ M} \)

Explanation

At \( \text{pH} = 3.0 \), \( [\text{H}^+] = 10^{-3}\text{ M} \). \( \frac{[\text{H}^+]}{K_a} = \frac{10^{-3}}{10^{-5}} = 100 \). So \( 1 + \frac{[\text{H}^+]}{K_a} = 101 \). \( S = \sqrt{4.0 \times 10^{-10} \times 101} = \sqrt{4.04 \times 10^{-8}} \approx 2.01 \times 10^{-4}\text{ M} \).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat