Chemistry · PYQ NEET UG 2018

The solubility of \( \mathrm{BaSO_4} \) in water is \( 2.42 \times 10^{-3} \text{ g L}^{-1} \) at \( 298 \text{ K} \). The value of its solubility product \( (\mathrm{K_{sp}}) \) will be (Given : molar mass of \( \mathrm{BaSO_4} = 233 \text{ g mol}^{-1} \))

1. A
   \( 1.08 \times 10^{-10} \text{ mol}^2 \text{ L}^{-2} \)
2. B
   \( 1.08 \times 10^{-12} \text{ mol}^2 \text{ L}^{-2} \)
3. C
   \( 1.08 \times 10^{-14} \text{ mol}^2 \text{ L}^{-2} \)
4. D
   \( 1.08 \times 10^{-8} \text{ mol}^2 \text{ L}^{-2} \)