Physics · JEE | THERMAL PROPERTIES OF MATTER
हिन्दीThe specific heat capacity \( s \) is given by \( s = \frac{1}{m} \frac{\Delta Q}{\Delta T} \). For a substance of mass \( 0.5\text{ kg} \), if supplying \( 2093\text{ J} \) of heat produces a temperature rise of \( 1\text{ K} \), the specific heat capacity in \( \text{J kg}^{-1}\text{ K}^{-1} \) is:
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Correct answer · Option D
4186
Explanation
\( s = \frac{2093}{0.5 \times 1} = 4186\text{ J kg}^{-1}\text{ K}^{-1} \).