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Physics · JEE | THERMAL PROPERTIES OF MATTER

हिन्दी

The specific heat capacity \( s \) is given by \( s = \frac{1}{m} \frac{\Delta Q}{\Delta T} \). For a substance of mass \( 0.5\text{ kg} \), if supplying \( 2093\text{ J} \) of heat produces a temperature rise of \( 1\text{ K} \), the specific heat capacity in \( \text{J kg}^{-1}\text{ K}^{-1} \) is:

  1. A
    8372
  2. B
    2093
  3. C
    1046
  4. D
    4186
View Answer & Solution

Correct answer · Option D

4186

Explanation

\( s = \frac{2093}{0.5 \times 1} = 4186\text{ J kg}^{-1}\text{ K}^{-1} \).
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