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Chemistry · THERMODYNAMICS

हिन्दी

The standard enthalpy of combustion of benzene, \( \text{C}_6\text{H}_6(l) \), is \( -3267.0\text{ kJ mol}^{-1} \). If the standard enthalpies of formation of \( \text{CO}_2(g) \) and \( \text{H}_2\text{O}(l) \) are \( -393.5\text{ kJ mol}^{-1} \) and \( -285.83\text{ kJ mol}^{-1} \) respectively, what is the standard enthalpy of formation (\( \Delta_f H^\ominus \)) of benzene?

  1. A
    \( -48.51\text{ kJ mol}^{-1} \)
  2. B
    \( -97.02\text{ kJ mol}^{-1} \)
  3. C
    \( +97.02\text{ kJ mol}^{-1} \)
  4. D
    \( +48.51\text{ kJ mol}^{-1} \)
View Answer & Solution

Correct answer · Option D

\( +48.51\text{ kJ mol}^{-1} \)

Explanation

\( \Delta_c H^\ominus = 6\Delta_f H^\ominus(\text{CO}_2) + 3\Delta_f H^\ominus(\text{H}_2\text{O}) - \Delta_f H^\ominus(\text{C}_6\text{H}_6) \). Hence, \( \Delta_f H^\ominus(\text{C}_6\text{H}_6) = 6(-393.5) + 3(-285.83) - (-3267.0) = -3218.49 + 3267.0 = +48.51\text{ kJ mol}^{-1} \).
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