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Chemistry · THERMODYNAMICS

हिन्दी

The standard enthalpy of combustion of glucose, \( \text{C}_6\text{H}_{12}\text{O}_6(s) \), is \( -2802.0\text{ kJ mol}^{-1} \). A person requires \( 8406\text{ kJ} \) of energy per day. What minimum mass of glucose must be consumed by the person to meet this energy demand via combustion?

  1. A
    \( 270\text{ g} \)
  2. B
    \( 180\text{ g} \)
  3. C
    \( 360\text{ g} \)
  4. D
    \( 540\text{ g} \)
View Answer & Solution

Correct answer · Option D

\( 540\text{ g} \)

Explanation

Moles needed = \( \frac{8406}{2802} = 3\text{ mol} \). Mass of glucose = \( 3\text{ mol} \times 180\text{ g mol}^{-1} = 540\text{ g} \).
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