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Chemistry · Some Basic Concepts of Chemistry

हिन्दी

The total number of valence electrons present in \( 4.2\text{ g} \) of azide ion (\( \text{N}_3^- \)) is (where \( N_{\text{A}} \) is the Avogadro constant):

  1. A
    \( 0.8 \, N_{\text{A}} \)
  2. B
    \( 3.2 \, N_{\text{A}} \)
  3. C
    \( 2.1 \, N_{\text{A}} \)
  4. D
    \( 1.6 \, N_{\text{A}} \)
View Answer & Solution

Correct answer · Option D

\( 1.6 \, N_{\text{A}} \)

Explanation

Molar mass of \( \text{N}_3^- = 42\text{ g/mol} \). Moles \( = 4.2/42 = 0.1\text{ mol} \). Valence electrons in one \( \text{N}_3^- = 3 \times 5 + 1 = 16 \). Total valence electrons \( = 0.1 \times 16 \, N_{\text{A}} = 1.6 \, N_{\text{A}} \).
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