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Physics · PYQ NEET UG 2023

हिन्दी

Two bodies of mass \( m \) and \( 9m \) are placed at a distance \( R \). The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (\( G = \) gravitational constant) :

  1. A
    \( -\frac{8Gm}{R} \)
  2. B
    \( -\frac{16Gm}{R} \)
  3. C
    \( -\frac{12Gm}{R} \)
  4. D
    \( -\frac{20Gm}{R} \)
View Answer & Solution

Correct answer · Option B

\( -\frac{16Gm}{R} \)

Explanation

Gravitational field is zero at distance \( x = \frac{R}{1+\sqrt{9/m*m}} = \frac{R}{4} \) from mass \( m \). The potential at this point is \( V = -\frac{Gm}{x} - \frac{G(9m)}{R-x} = -\frac{4Gm}{R} - \frac{12Gm}{R} = -\frac{16Gm}{R} \).
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