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Physics · Electrostatic Potential

हिन्दी

Two charges \( q_1 \) and \( q_2 \) are placed at position vectors \( \mathbf{r}_1 \) and \( \mathbf{r}_2 \) in an external electric field with potential \( V(\mathbf{r}) \). If \( r_{12} \) is the separation between them, the total electrostatic potential energy of the system is:

  1. A
    \( q_1 V(\mathbf{r}_1) + q_2 V(\mathbf{r}_2) \)
  2. B
    \( q_1 V(\mathbf{r}_1) + q_2 V(\mathbf{r}_2) + \frac{q_1 q_2}{4\pi\varepsilon_0 r_{12}} \)
  3. C
    \( \frac{q_1 q_2}{4\pi\varepsilon_0 r_{12}} \)
  4. D
    \( (q_1 + q_2)[V(\mathbf{r}_1) - V(\mathbf{r}_2)] + \frac{q_1 q_2}{4\pi\varepsilon_0 r_{12}^2} \)
View Answer & Solution

Correct answer · Option B

\( q_1 V(\mathbf{r}_1) + q_2 V(\mathbf{r}_2) + \frac{q_1 q_2}{4\pi\varepsilon_0 r_{12}} \)

Explanation

The total energy is the work required to assemble both charges against the external field plus their mutual electrostatic interaction: U = q1 V(r1) + q2 V(r2) + q1 q2 / (4 pi eps0 r12).
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