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Physics · MOTION IN A PLANE
हिन्दीTwo equal vectors \( \mathbf{A} \) and \( \mathbf{B} \), each of magnitude \( 10\text{ units} \), are inclined at an angle of \( 60^\circ \) to each other. Calculate the magnitude of the vector difference \( |\mathbf{A} - \mathbf{B}| \).
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Correct answer · Option B
\( 10\text{ units} \)
Explanation
\( |\mathbf{A} - \mathbf{B}| = \sqrt{A^2 + B^2 - 2AB\cos 60^\circ} = \sqrt{100 + 100 - 200(0.5)} = \sqrt{100} = 10\text{ units} \).
