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Physics · KINETIC THEORY

हिन्दी

Two ideal gases \( A \) and \( B \) have molar masses in the ratio \( M_A : M_B = 1 : 2 \). A mixture is prepared containing equal masses of both gases at a temperature \( T \). If the total pressure of the mixture is \( P \), what is the partial pressure of gas \( A \)?

  1. A
    \( \frac{3}{4} P \)
  2. B
    \( \frac{1}{3} P \)
  3. C
    \( \frac{1}{2} P \)
  4. D
    \( \frac{2}{3} P \)
View Answer & Solution

Correct answer · Option D

\( \frac{2}{3} P \)

Explanation

Let mass of each gas be \( m \). Moles of \( A \) is \( n_A = m/M_A \) and \( n_B = m/M_B = m/(2M_A) = n_A/2 \). The mole fraction of \( A \) is \( x_A = \frac{n_A}{n_A + n_B} = \frac{n_A}{n_A + 0.5 n_A} = \frac{2}{3} \). Hence, partial pressure \( P_A = x_A P = \frac{2}{3} P \).
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