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Physics · JEE | Moving Charges and Magnetism
हिन्दीTwo long parallel wires separated by \( 10\text{ cm} \) carry equal currents in opposite directions. If the force per unit length on each wire is \( 2.0 \times 10^{-4}\text{ N/m} \), the magnitude of the current in each wire is:
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Correct answer · Option B
\( 10\text{ A} \)
Explanation
Using \( f = \frac{\mu_0 I^2}{2\pi d} \implies 2.0 \times 10^{-4} = \frac{4\pi \times 10^{-7} I^2}{2\pi \times 0.1} \implies I^2 = 100 \implies I = 10\text{ A} \).
