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Physics · PYQ NEET UG 2019(1)

हिन्दी

Two point charges A and B, having charges \( +Q \) and \( -Q \) respectively, are placed at certain distance apart and force acting between them is \( F \). If \( 25\% \) charge of A is transferred to B, then force between the charges becomes:

  1. A
    \( \frac{16F}{9} \)
  2. B
    \( \frac{4F}{3} \)
  3. C
    F
  4. D
    \( \frac{9F}{16} \)
View Answer & Solution

Correct answer · Option D

\( \frac{9F}{16} \)

Explanation

Initial force \( F = k\frac{Q^2}{r^2} \). New charges are \( q_1 = Q - 0.25Q = 0.75Q \) and \( q_2 = -Q + 0.25Q = -0.75Q \). New force \( F' = k\frac{(0.75Q)^2}{r^2} = \frac{9}{16}F \).
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