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Physics · JEE27-M01 | Atoms and Nuclei

हिन्दी

Two deuterons undergo fusion ²H+²H→³He+n with negligible initial kinetic energy. Total binding energies of ²H and ³He are 2.22 MeV and 7.72 MeV. Neglect photon emission and use final mass ratio m(³He):m(n)=3:1. The neutron kinetic energy is:

  1. A

    0.82 MeV

  2. B

    2.46 MeV

  3. C

    3.28 MeV

  4. D

    4.44 MeV

View Answer & Solution

Correct answer · Option B

2.46 MeV

Explanation

Released energy Q=7.72−2(2.22)=3.28 MeV. Initial momentum is negligible, so final momenta are equal and opposite. Nonrelativistically kinetic energy is inversely proportional to mass: Tn/THe=3. Hence Tn=3Q/4=2.46 MeV.

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