Physics · JEE27-M01 | Atoms and Nuclei
हिन्दीTwo deuterons undergo fusion ²H+²H→³He+n with negligible initial kinetic energy. Total binding energies of ²H and ³He are 2.22 MeV and 7.72 MeV. Neglect photon emission and use final mass ratio m(³He):m(n)=3:1. The neutron kinetic energy is:
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Correct answer · Option B
2.46 MeV
Explanation
Released energy Q=7.72−2(2.22)=3.28 MeV. Initial momentum is negligible, so final momenta are equal and opposite. Nonrelativistically kinetic energy is inversely proportional to mass: Tn/THe=3. Hence Tn=3Q/4=2.46 MeV.