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Physics · PYQ NEET UG 2016(2)

हिन्दी

Two rotating bodies A and B of masses m and 2 m with moments of inertia \( I_A \) and \( I_B \) (\( I_B > I_A \)) have equal kinetic energy of rotation. If \( L_A \) and \( L_B \) be their angular momenta respectively, then

  1. A
    \( L_A > L_B \)
  2. B
    \( L_A = \frac{L_B}{2} \)
  3. C
    \( L_A = 2L_B \)
  4. D
    \( L_B > L_A \)
View Answer & Solution

Correct answer · Option D

\( L_B > L_A \)

Explanation

Rotational kinetic energy \( K = \frac{L^2}{2I} \). Since K is equal for both, \( L = \sqrt{2IK} \). Therefore, \( \frac{L_A}{L_B} = \sqrt{\frac{I_A}{I_B}} \). Since \( I_B > I_A \), we get \( L_B > L_A \).

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