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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION

हिन्दी

Two uniform thin rods each of length \( L \) and mass \( M \) are joined perpendicularly at their midpoints to form a symmetric cross. The moment of inertia of this cross about an axis perpendicular to the plane containing both rods and passing through their intersection point is:

  1. A
    \( \frac{ML^2}{6} \)
  2. B
    \( \frac{ML^2}{12} \)
  3. C
    \( \frac{ML^2}{4} \)
  4. D
    \( \frac{ML^2}{3} \)
View Answer & Solution

Correct answer · Option A

\( \frac{ML^2}{6} \)

Explanation

For each rod, the moment of inertia about the perpendicular axis through its midpoint is \( I_1 = \frac{1}{12}ML^2 \). For both rods together, \( I = I_1 + I_2 = \frac{1}{12}ML^2 + \frac{1}{12}ML^2 = \frac{ML^2}{6} \).
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