Physics · JEE | Electric Charges and Fields
हिन्दीWhat is the acceleration of an electron when subjected to an electric force of magnitude \( 2.3 \times 10^{-8}\,\text{N} \) due to a proton? (Take \( m_e = 9.11 \times 10^{-31}\,\text{kg} \))
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Correct answer · Option D
\( 2.5 \times 10^{22}\text{ m/s}^2 \)
Explanation
Using Newton's second law, \( a = \frac{F}{m_e} = \frac{2.3 \times 10^{-8}}{9.11 \times 10^{-31}} = 2.5 \times 10^{22}\,\text{m/s}^2 \).