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Physics · JEE | Electrostatic Potential and Capacitance

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एक बिंदु आवेश \( Q \) से \( r \) दूरी पर स्थिरवैद्युत विभव \( V(r) \) क्या है?

  1. A
    \( V(r) = \frac{1}{4\pi\varepsilon_0} Q r \)
  2. B
    \( V(r) = \frac{1}{4\pi\varepsilon_0} \frac{Q}{r^2} \)
  3. C
    \( V(r) = \frac{1}{4\pi\varepsilon_0} \frac{Q^2}{r} \)
  4. D
    \( V(r) = \frac{1}{4\pi\varepsilon_0} \frac{Q}{r} \)
उत्तर और समाधान देखें

सही उत्तर · विकल्प D

\( V(r) = \frac{1}{4\pi\varepsilon_0} \frac{Q}{r} \)

व्याख्या

The potential due to a point charge \( Q \) at distance \( r \) is derived by integrating the electric field: \( V(r) = \frac{1}{4\pi\varepsilon_0} \frac{Q}{r} \).
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