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Physics · JEE | GRAVITATION

हिन्दी

What is the expression for the total mechanical energy of a particle of mass \( m \) moving in a circular orbit of radius \( a \) about a massive body \( M \) (\( M \gg m \))?

  1. A
    \( E = -\frac{GMm}{a} \)
  2. B
    \( E = \frac{GMm}{a} \)
  3. C
    \( E = \frac{GMm}{2a} \)
  4. D
    \( E = -\frac{GMm}{2a} \)
View Answer & Solution

Correct answer · Option D

\( E = -\frac{GMm}{2a} \)

Explanation

The total mechanical energy of a circular orbit of radius \( a \) is \( E = K + V = \frac{GMm}{2a} - \frac{GMm}{a} = -\frac{GMm}{2a} \).
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