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Mathematics · JEE | CONTINUITY AND DIFFERENTIABILITY

हिन्दी

What is the formula for logarithmic differentiation of \( y = [u(x)]^{v(x)} \)?

  1. A
    \( y [ v(x) \log u(x) ] \)
  2. B
    \( y [ v'(x) \log u(x) + v(x) \frac{u'(x)}{u(x)} ] \)
  3. C
    \( v(x) [u(x)]^{v(x)-1} u'(x) \)
  4. D
    \( [u(x)]^{v(x)} v'(x) \)
View Answer & Solution

Correct answer · Option B

\( y [ v'(x) \log u(x) + v(x) \frac{u'(x)}{u(x)} ] \)

Explanation

Taking logs gives \( \log y = v(x)\log u(x) \). Differentiating both sides gives \( \frac{1}{y}\frac{dy}{dx} = v'(x)\log u(x) + v(x)\frac{u'(x)}{u(x)} \).
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