Physics · JEE | Moving Charges and Magnetism
हिन्दीWhat is the magnetic field at the center of a circular loop of radius \( R \) carrying steady current \( I \)?
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Correct answer · Option C
\( \frac{\mu_0 I}{2R} \)
Explanation
Putting \( x = 0 \) in the axial magnetic field formula \( B = \frac{\mu_0 I R^2}{2(x^2+R^2)^{3/2}} \) yields \( B_0 = \frac{\mu_0 I}{2R} \).