OnlineCBT Logo OnlineCBT

Physics · JEE | Moving Charges and Magnetism

हिन्दी

What is the magnetic field at the centre of a circular coil of radius \( 5\text{ cm} \) having \( 50\text{ turns} \) and carrying a current of \( 2\text{ A} \)?

  1. A
    \( 1\pi \times 10^{-4}\text{ T} \)
  2. B
    \( 2\pi \times 10^{-4}\text{ T} \)
  3. C
    \( 8\pi \times 10^{-4}\text{ T} \)
  4. D
    \( 4\pi \times 10^{-4}\text{ T} \)
View Answer & Solution

Correct answer · Option D

\( 4\pi \times 10^{-4}\text{ T} \)

Explanation

Using \( B = \frac{\mu_0 N I}{2R} = \frac{4\pi \times 10^{-7} \times 50 \times 2}{2 \times 0.05} = 4\pi \times 10^{-4}\text{ T} \).
Address Contact

+91 9694780911

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 9694780911


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat