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Physics · JEE | Electric Charges and Fields

हिन्दी

What is the magnitude of force on each pair of charges \( q \) and \( -q \) placed at the vertices of an equilateral triangle of side \( l \)?

  1. A
    \( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l} \)
  2. B
    \( F = \frac{1}{4\pi\varepsilon_0} \frac{\sqrt{3} q^2}{l^2} \)
  3. C
    \( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2} \)
  4. D
    \( F = \frac{1}{4\pi\varepsilon_0} \frac{2q^2}{l^2} \)
View Answer & Solution

Correct answer · Option C

\( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2} \)

Explanation

The magnitude of electrostatic attraction or repulsion between any pair of charges separated by distance \( l \) is \( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2} \).
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