Physics · JEE | Electric Charges and Fields
हिन्दीWhat is the magnitude of force on each pair of charges \( q \) and \( -q \) placed at the vertices of an equilateral triangle of side \( l \)?
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Correct answer · Option C
\( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2} \)
Explanation
The magnitude of electrostatic attraction or repulsion between any pair of charges separated by distance \( l \) is \( F = \frac{1}{4\pi\varepsilon_0} \frac{q^2}{l^2} \).