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Physics · JEE | LAWS OF MOTION

हिन्दी

What is the maximum acceleration of a train in which a box lying on its floor remains stationary, given that the coefficient of static friction between the box and the train floor is \( \mu_s \) and acceleration due to gravity is \( g \)?

  1. A
    \( a_{\max} = \frac{g}{\mu_s} \)
  2. B
    \( a_{\max} = \mu_s g \)
  3. C
    \( a_{\max} = \sqrt{\mu_s g} \)
  4. D
    \( a_{\max} = \mu_s^2 g \)
View Answer & Solution

Correct answer · Option B

\( a_{\max} = \mu_s g \)

Explanation

Since static friction provides the maximum acceleration, \( ma_{\max} = f_{s,\max} = \mu_s N = \mu_s mg \), giving \( a_{\max} = \mu_s g \).
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