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Mathematics · JEE | INVERSE TRIGONOMETRIC FUNCTIONS
हिन्दीWhat is the principal value of \( \sec^{-1}(\frac{2}{\sqrt{3}}) \)?
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Correct answer · Option B
\( \frac{\pi}{6} \)
Explanation
The principal value branch of \( \sec^{-1} \) is \( [0, \pi] - \{\frac{\pi}{2}\} \). Since \( \sec(\frac{\pi}{6}) = \frac{2}{\sqrt{3}} \), the principal value is \( \frac{\pi}{6} \).
