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Mathematics · JEE | CONIC SECTIONS

हिन्दी

What is the radius of the circle given by the equation \( x^2 + y^2 + 8x + 10y - 8 = 0 \)?

  1. A
    \( 5 \)
  2. B
    \( 7 \)
  3. C
    \( 6 \)
  4. D
    \( 8 \)
View Answer & Solution

Correct answer · Option B

\( 7 \)

Explanation

Completing the square gives \( (x+4)^2 + (y+5)^2 = 8 + 16 + 25 = 49 = 7^2 \), so the radius is \( r = 7 \).

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