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Mathematics · JEE | INTEGRALS

हिन्दी

What is the value of \( \int \frac{x^2 + 1}{(x-2)(x-3)} dx \) when expressed in terms of polynomials and logarithmic components?

  1. A
    \( x + 5 \log |x-2| - 10 \log |x-3| + C \)
  2. B
    \( x - 5 \log |x-2| + 10 \log |x-3| + C \)
  3. C
    \( x - 10 \log |x-2| + 5 \log |x-3| + C \)
  4. D
    \( 1 - 5 \log |x-2| + 10 \log |x-3| + C \)
View Answer & Solution

Correct answer · Option B

\( x - 5 \log |x-2| + 10 \log |x-3| + C \)

Explanation

By polynomial division and partial fractions, \( \frac{x^2+1}{x^2-5x+6} = 1 - \frac{5}{x-2} + \frac{10}{x-3} \), integrating gives \( x - 5\log|x-2| + 10\log|x-3| + C \).
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