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Mathematics · JEE | INTEGRALS

हिन्दी

What is the value of the definite integral \( \int_{1}^{\sqrt{3}} \frac{dx}{1+x^2} \)?

  1. A
    \( \frac{\pi}{3} \)
  2. B
    \( \frac{\pi}{4} \)
  3. C
    \( \frac{\pi}{12} \)
  4. D
    \( \frac{\pi}{6} \)
View Answer & Solution

Correct answer · Option D

\( \frac{\pi}{6} \)

Explanation

Integrating gives \( [\tan^{-1} x]_1^{\sqrt{3}} = \frac{\pi}{3} - \frac{\pi}{4} = \frac{\pi}{12} \).
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