Mathematics · JEE | INTEGRALS
हिन्दीWhat is the value of the definite integral \( \int_{1}^{\sqrt{3}} \frac{dx}{1+x^2} \)?
View Answer & Solution
Correct answer · Option D
\( \frac{\pi}{6} \)
Explanation
Integrating gives \( [\tan^{-1} x]_1^{\sqrt{3}} = \frac{\pi}{3} - \frac{\pi}{4} = \frac{\pi}{12} \).