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Physics · JEE | WORK, ENERGY AND POWER

हिन्दी

When a car of mass \( m \) moving with initial speed \( v \) collides with a horizontally mounted spring of spring constant \( k \) on a rough surface with coefficient of kinetic friction \( \mu \), the quadratic equation determining the maximum compression \( x_m \) is:

  1. A
    \( \frac{1}{2}kx_m^2 + \frac{1}{2}\mu mg x_m - \frac{1}{2}mv^2 = 0 \)
  2. B
    \( \frac{1}{2}kx_m^2 - \mu mg x_m + \frac{1}{2}mv^2 = 0 \)
  3. C
    \( kx_m^2 + \mu mg x_m - mv^2 = 0 \)
  4. D
    \( \frac{1}{2}kx_m^2 + \mu mg x_m - \frac{1}{2}mv^2 = 0 \)
View Answer & Solution

Correct answer · Option D

\( \frac{1}{2}kx_m^2 + \mu mg x_m - \frac{1}{2}mv^2 = 0 \)

Explanation

By work-energy theorem, loss in kinetic energy equals work done by spring and friction: \( \frac{1}{2}mv^2 = \frac{1}{2}kx_m^2 + \mu mg x_m \), leading to \( \frac{1}{2}kx_m^2 + \mu mg x_m - \frac{1}{2}mv^2 = 0 \).
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