OnlineCBT Logo OnlineCBT

Chemistry · JEE | Thermodynamics (Chemical Thermodynamics)

हिन्दी

Which of the following represents the expression for the internal energy change of vaporization (\( \Delta_{\text{vap}} U \)) in terms of standard enthalpy of vaporization (\( \Delta_{\text{vap}} H^\ominus \))?

  1. A
    \( \Delta_{\text{vap}} U = \Delta_{\text{vap}} H^\ominus + \Delta n_g RT \)
  2. B
    \( \Delta_{\text{vap}} U = \Delta_{\text{vap}} H^\ominus \times \Delta n_g RT \)
  3. C
    \( \Delta_{\text{vap}} U = \Delta n_g RT - \Delta_{\text{vap}} H^\ominus \)
  4. D
    \( \Delta_{\text{vap}} U = \Delta_{\text{vap}} H^\ominus - \Delta n_g RT \)
View Answer & Solution

Correct answer · Option D

\( \Delta_{\text{vap}} U = \Delta_{\text{vap}} H^\ominus - \Delta n_g RT \)

Explanation

From \( \Delta H = \Delta U + \Delta n_g RT \), rearranging for internal energy change gives \( \Delta_{\text{vap}} U = \Delta_{\text{vap}} H^\ominus - \Delta n_g RT \).
Address Contact

+91 9694780911

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 9694780911


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat